It has also determined that the number of repair claims filed each week is a random variable

which can take values 1, 2, 4, 5, 6, 7, 8, 9. The probability of having 1 or 9 claims in a week is

equal. The probability that there are 2, 6, 7 or 8 claims in a week is twice the probability of

there being a single claim. The probability that there are 4 claims in a week is twice the

probability that there are 2 claims in a week. The probability that there are 5 claims in a week is

6 times the probability that there is a single claim in a week. The dollar amount per claim fits a

normal distribution with a mean claim amount of $2000 and a standard deviation of $400.

In addition to repair claims, the company also receives claims for cars that have been “totaled”

and cannot be repaired. There is a 20% chance in any week of receiving this type of claim. The

claims for “totaled” cars cost has a uniform distribution, in the range $10000 to $35000. Not all

repair claims are legitimate: 1% of the repair claims filed are rejected. Of the “totaled” claims

filed, 0.5% of them are rejected.

I'm not sure how to make the formulas for paragraph 1. And then I don't know how to incorporate the probability into the random uniform distribution and how to incorporate the reject variable.

Any help would be greatly appreciated.